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What is the y value of the vertex of 4x^2+8x-8

What is the y value of the vertex of 4x^2+8x-8
asked 217k views
5 votes
What is the y value of the vertex of 4x^2+8x-8

asked
User Pranjal Diwedi
by
7.4k points

2 Answers

3 votes
Vertex x=-b/2a
Ax^2+bx+c
X=-8/2 (4)
X=-8/8
X=-1
Plug in
4x^2+8x-8
4 (-1)^2+8 (-1)-8
4 (1)-8-8
4-8-8
-4-8
-12
Vertex= (-1,-12)

answered
User Jason Holloway
by
8.6k points
3 votes
Vertex x=-b/2a
Ax^2+bx+c
X=-8/2 (4)
X=-8/8
X=-1
Plug in
4x^2+8x-8
4 (-1)^2+8 (-1)-8
4 (1)-8-8
4-8-8
-4-8
-12
Vertex= (-1,-12)
answered
User Yasir Majeed
by
8.6k points
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