Question

a square with sides of 3 square roots of 2 is inscribed in a circle.What is the area of one of the sectors formed by the radii to the vertices of the square

Answer 1

first you take a right triangle out then you

Answer 2

so hmm notice the picture below

recall, a square has all angles to 90°, thus, the diagonals bisecting any of the vertices, will make a 45° on each

anyhow,
`\bf \textit{area of a sector of a circle}\\\\ A=\cfrac{\theta\pi r^2}{360}\qquad \begin{cases} \theta=\textit{central angle in degrees}\\ r=radius\\ ----------\\ \theta=90\\ r=3 \end{cases}`