Question

Find the volume of a frustum of a right pyramid whose lower base is a square with a side 5 in. and whose upper base is a square with a side 3 in., and whose altitude is 12 in. Round your answer to the nearest whole number.

A. 1036 cu in.
B. 47 cu in.
C. 226 cu in.
D. 196 cu in.
I'll give u extra points if u answer this

Answer 1

the volume of the frustum =(1/3)h[a1+a2]+√(a1 a2) where a1=bottom area,a2=top area and h=height
a1=100sa.inch
a2=25 sq.inch and
h=12inch
so the volume =(1/3)(12)[100+25+√(100*25)]
=4*[125+50]
=4*175=700 cubic inches or [inch cubed]