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Enter the equation of the circle described below. Center (3,-2), radius = 5

Enter the equation of the circle described below. Center (3,-2), radius = 5
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Enter the equation of the circle described below.

Center (3,-2), radius = 5

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User Vinoth Krishnan
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8.5k points

2 Answers

4 votes

Answer:


Explanation:


answered
User Janak Prajapati
by
7.8k points
2 votes
Apply the standard equation of a circle:

(x-h)²+(y-k)²=R²

== (x-3)²+(y+2)²=25
answered
User Indy
by
7.6k points
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