Let's find the slope first...(y2-y1)/(x2-x1)
m=(6-1)/(0--5)=5/5=1
y=x+b, using point (0,6)
6=0+b so b=5...
y=x+6
Standard form has both variables on one side and a constant on the other side and by convention the coefficient of x is positive so:
y-x=6
x-y=-6 This is standard form...
Now "slope equation" is murky...
There is the point-slope form: (y-y1)=m(x-x1) which in this case is:
Using point (0,6)...
(y-6)=1(x-0)
y-6=x
And then there is slope intercept form which is y=mx+b, which we found earlier:
y=x+6