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Sin^2xcsc^2x=sin^2x+cos^2x

Sin^2xcsc^2x=sin^2x+cos^2x
asked 37.5k views
5 votes
Sin^2xcsc^2x=sin^2x+cos^2x

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User Cartalot
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1 Answer

2 votes
The second part = 1

the second part could be written sin²x.(1/sin²x), since cscx =1/sinx

hence 1 = 1
answered
User Benny Ae
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