Question

Which linear inequality could represent the given table of values?

y < –2x + 3
y ≤ –2x + 3
y > –x – 3
y ≤ –x – 3

Answer 1

b

Explanation:

Answer 2

Answer: The answer is (B) y ≤ –2x + 3 .

Step-by-step explanation: We are to select the correct linear inequality that could represent the table of values given in the question.

If (x, y) = (-4, -1), then

`y=-1,\\\\-2x+3=-2*(-4)+3=8+3=11.`

So, y < -2x + 3.

If (x, y) = (-2, 4), then

`y=4,\\\\-2x+3=-2*(-2)+3=4+3=7.`

So, y < -2x + 3.

If (x, y) = (3, -3), then

`y=-3,\\\\-2x+3=-2* 3+3=-6+3=-3.`

So, y = -2x + 3.

If (x, y) = (3, -4), then

`y=-4,\\\\-2x+3=-2* 3+3=-6+3=-3.`

So, y < -2x + 3.

Therefore, we have y is either less than or equal to (-2x + 3).

Thus, y ≤ –2x + 3 and (B) is the correct option.