Question

What are the roots to the quadratic equation with the following coefficients in standard form? a=2, b=-3, c=-4

Answer 1

The roots are
`(3 +/- √(41))/(4)`.

You can find the roots of any quadratic using the following equation.

`\frac{-b +/- \sqrt{b^(2)- 4ac}}{2a}`

Now we can place each of the values in their respective spots.

`\frac{3 +/- \sqrt{-3^(2)- 4(2)(-4)}}{2(2)}`

`(3 +/- √(9 + 32))/(4)`

`(3 +/- √(41))/(4)`

Then these are your roots.