asked 58.9k views
2 votes
An electrochemical cell is based on the following two half-reactions: Ox: Sn(s)→Sn2+(aq, 1.85 M )+2e− Red: ClO2(g, 0.150 atm )+e−→ClO−2(aq, 2.00 M )

Compute the cell potential at 25 ∘C.

Ecell= ______V

asked
User Ceylan
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7.6k points

2 Answers

4 votes

Final answer:

The cell potential of an electrochemical cell can be calculated using the Nernst equation. The anode and cathode are determined based on the standard reduction potentials. By subtracting the anode potential from the cathode potential, the cell potential can be determined.

Step-by-step explanation:

The cell potential of an electrochemical cell can be calculated using the Nernst equation. First, we need to determine the anode and cathode based on the standard reduction potentials. The reduction potential with the higher value will be the cathode, while the one with the lower value will be the anode. By subtracting the anode potential from the cathode potential, we can determine the cell potential.

answered
User Miguel Trias
by
8.4k points
2 votes
We are given
Ox: Sn(s) → Sn2+ (aq, 1.85 M) + 2e−
Red: ClO2 (g, 0.150 atm ) + e− → ClO−2 (aq, 2.00 M)

We are to compute the cell potential at 25 °C

We simply have to look for the standard potentials for each of the reactions and subtract the redox standard potential from the oxidation standard potential.

From literature and after doing the operation, the answer is
Ecell = 2.2 V
answered
User Cderv
by
8.7k points
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