Question

How many combinations of 3 students can a teacher choose from 32 students?

A.
96


B.
4960


C.
29,760


D.
32,768

Answer 1

The answer is: [B]: "4960" .
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Step-by-step explanation:
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32C3 = [(32!)] / [ 3! *(32-3)! ] ;

= [(32!)] / [ 3! *(29!) ]

= (32*31*30) / (1*2*3) = 29760 / 6 = 4960 .
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