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The area of a rectangle is 5x^3+19+6x-18 with length x + 3. Using synthetic division, what is the width of the rectangle?

The area of a rectangle is 5x^3+19+6x-18 with length x + 3. Using synthetic division, what is the width of the rectangle?
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The area of a rectangle is 5x^3+19+6x-18 with length x + 3. Using synthetic division, what is the width of the rectangle?

asked
User Majeda
by
8.2k points

2 Answers

7 votes

Answer:

5x^2 + 4x - 6

Explanation:

answered
User VIKAS KOHLI
by
8.6k points
3 votes
5 19 6 -18
-3
-15 -12 18

5 4 -6 0

Therefore, the width is 5x^2 + 4x - 6
answered
User SmileBot
by
9.0k points
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