Question

a bomber takes off at 500kph. a fighter setting out 2.5hrs later flies at 750kph. how long will it take for the fighter to catch the bomber, and how far will the bomber have travelled at this time. show working

Answer 1

b=500(t+2.5), f=750t the fighter catches the bomber when b=f so

500t+1250=750t

250t=1250

t=5

The fighter will catch up with the bomber in 5 hours.

The bomber will have traveled"

b=500(t+2.5) and t=5 so

500*7.5= 3750km