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How many moles of Fe2O3 are in 241 g of the compound?

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asked Dec 27, 2018 213k views

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How many moles of Fe2O3 are in 241 g of the compound?

Chemistry
college

Daniel Eriksson asked

by Daniel Eriksson

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1 Answer

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n=m/M
= 241 g /159.69 mol/g
=1.50917

Sstauross answered Jan 1, 2019

by Sstauross

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How many moles of Fe2O3 are in 241 g of the compound?

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