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Tan(θ)/sec(θ) − cos(θ)

Tan(θ)/sec(θ) − cos(θ)
asked 41.5k views
4 votes
Tan(θ)/sec(θ) − cos(θ)

asked
User Kikiwora
by
8.4k points

1 Answer

2 votes
sin(theta)- cos(theta)
answered
User Dan Fitch
by
8.3k points
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