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What is the poh of a 4.5x10^-3 m oh- solution?

asked
User Carven
by
7.3k points

2 Answers

7 votes
The formula for pOH is -log(M)

So, all we need to do is plug in that number! -log(4.5x10^-3)
That gives us 2.3, so the pOH is 2.3 :)
answered
User Neiya
by
8.9k points
3 votes

Answer: The pOh of the given solution is 2.35

Step-by-step explanation:

pOH is defined as the negative logarithm of hydroxide ion concentration present in a solution. The equation used to represent pOH of the solution follows:


pOH=-\log[OH^-]

We are given:


[OH^-]=4.5* 10^(-3)M

Putting values in above equation, we get:


pOH=-\log(4.5* 10^(-3))


pOH=2.35

Hence, pOH of the given solution is 2.35

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