asked 25.3k views
3 votes
Convert the polar representation of this complex number into its rectangular form: z=4(cos150°+ i sin150°) *the i before sin is an imaginary number*

asked
User Mmarie
by
7.7k points

2 Answers

7 votes
Use z=a+bi=|z|(cos (theta)+i sin(theta)) to find the complex number solutions. z0=z0= -2sqrt3 + 2i
answered
User IlPittiz
by
8.7k points
3 votes

Answer:


z=2(-√(3)+i)

Explanation:

The given polar representation of the complex number is:


z=4(cos(150)^(\circ)+isin(150)^(\circ))

Thus, by solving the above equation, we have


z=4(cos(90+60)+isin(90+60))


z=4(-sin60^(\cic)+icos60^(\circ))


z=4((√(3))/(2)+i(1)/(2)


z=2(-√(3)+i)

which is the required rectangular form of the given polar complex number.

answered
User Jonathan Irwin
by
8.3k points

Related questions

asked Aug 21, 2020 72.3k views
Antonio Narkevich asked Aug 21, 2020
by Antonio Narkevich
7.8k points
2 answers
2 votes
72.3k views
asked May 22, 2022 186k views
Kidshaw asked May 22, 2022
by Kidshaw
7.9k points
1 answer
16 votes
186k views
1 answer
2 votes
27.3k views
Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.