Question

F(x)-x^2+6x+8 how do you convert this form to standard form and vertex form

Answer 1

you complete the square

Vertex form is


`f(x) = (x - h)^2 + k~~~~~~~the~~vertex ~~is~~(h, k)`

so break it into parts


`f(x) = (x^2 + 6x + ??) + 8 - ??`

to keep the equation in balance to add and subtract the same value

so value ?? is


`?? = ( (6)/(2) )^2`

then factor the perfect square