The graph of y=11x^2+c is a parabola with a vertex at the origin ?

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asked Nov 8, 2018 196k views

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Naveen Ramanathan · Answer 1 · 2018-11-12T23:33:55+0000

This question is worded oddly.

y = 11
x^(2)

is a parabola with a vertex at the origin. (0,0)

Depending on what 'c' is, that will shift the parabola positive or negative. Therefore in general terms, the vertex will be at the location of 'c'.

The graph of y=11x^2+c is a parabola with a vertex at the origin ?

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