Question

Solve sin^2x+cos2x-1/4=0

Answer 1

`sin^(2)x + cos2x - (1)/(4) = 0`

`sin^(2)x + cos^(2)x - sin^(2)x = (1)/(4)`

`cos^(2)x = (1)/(4)`

`cos(x) = \pm (1)/(2)`


`x = \pm (\pi)/(3)`
General solutions:
`x = \pi(n - (1)/(3))` and
`x = \pi(n + (1)/(3))`