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Vertex for the function y= -2x^2+8x-5

Vertex for the function y= -2x^2+8x-5
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4 votes
Vertex for the function y= -2x^2+8x-5

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User Moien
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8.0k points

1 Answer

4 votes
hello :
-2x²+8x-5 = -2(x²-4x+5/2)
= -2(x²-2(2)(x)+2²-2² +5/2)
= -2 ( (x-2)² -3/2)
-2x²+8x-5 = -2(x-2)² +3
the vertex is the point A(2,3)

answered
User Josue Yeray
by
8.6k points
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