asked 72.1k views
3 votes
John predicts his football team will score 67 points in the next game. If John's team actually scored 42 points, what was John's percent error? Round your answer to the nearest tenth of a percent.

asked
User Abuteau
by
8.6k points

2 Answers

2 votes

Final answer:

John's percent error in his prediction of his football team's score is approximately 37.3% when rounded to the nearest tenth of a percent.

Step-by-step explanation:

To calculate the percent error of John's prediction, you need to compare the actual score to the predicted score. The formula to find percent error is:

Percent Error = |(Actual Value - Predicted Value)| / |Predicted Value| × 100%

Let's apply this formula using the values given:

Actual Score = 42 points
Predicted Score = 67 points

Percent Error = |(42 - 67)| / |67| × 100%
= |(-25)| / 67 × 100%
= 25 / 67 × 100%
≈ 37.3134%

When rounded to the nearest tenth of a percent, the percent error is 37.3%.

answered
User Dharminder
by
8.7k points
4 votes
The answer is 37.3%

Hope I helped
answered
User RedCollarPanda
by
7.9k points
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