Question

A steel ball is dropped from a height and hits the ground 6.7 seconds after its release. From what height (in feet) was the ball released?

Answer 1

Explanation:

Acceleration = g = 32.17ft/s²

Initial velocity = 0ft/s

Time taken = 6.7s

Using Kinematics,

we have s = ut + 0.5at².

=> s = (0)(6.7) + 0.5(32.17)(6.7)²

=> s = 722.06ft.