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Find the 20th term of an arithmetic sequence with a first term of 3 and a common difference of 5.

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User ChenBr
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2 Answers

1 vote
nth term = a + (n-1)d where a = first term and d = common difference just plug in your values (note n = 20)


answered
User Maryse
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2 votes

Answer: The required 20-th term of the given arithmetic sequence is 98.

Step-by-step explanation: We are given to find the 20th term of an arithmetic sequence with first term 3 and common difference 5.

We know that

the n-th term of an arithmetic sequence with first term a and common difference d is given by


a_n=a+(n-1)d.

For the given arithmetic sequence, we have

first term, a = 3

and

common ratio, d = 5.

Therefore, the 20-th term pf the arithmetic sequence will be


a_(20)=a+(n-1)d=3+(20-1)*5=3+19*5=3+95=98.

Thus, the required 20-th term of the given arithmetic sequence is 98.

answered
User Gord Thompson
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7.5k points

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