Question

An ideal gas at 27°c is contained in a piston that ensures that its pressure will always be constant. raising the temperature of the gas causes it to expand. at what temperature will the gas take up twice its original volume?

Answer 1

PV = nrT
Pnr = const therefore

T has to be in Kelvin so
`T_(1)`
`= 27+273 = 300K`

`(T _(1) )/(V _(1)) = (T _(2) )/(V _(2))`


`V _(2) = 2V _(1)`

therefore

`T _(2) = 2V _(1) (T_(1))/(V_(1))`

`T_(2) = 2T_(1) = 600K = 327`°