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5 votes
∠BEC is formed inside a circle by two intersecting chords. If minor arc BD = 94 and minor arc CA = 166, what is the measure of ∠ BEC?

2 Answers

5 votes
260................................................
answered
User Mike Debela
by
7.6k points
3 votes

Answer: The measure of ∠BEC = 50°.

Explanation:

Since we have given that

∠BEC is formed inside a circle by two intersecting chords.

and the value of minor arc BD = 94

The value of major arc CA = 166

We need to find the measure of ∠ BEC.

As we know theorem, the angle AEC is equal to half the sum of the intercepted arcs.

We will use to find the intercepted angles when two chords got intersected i.e.


m\angle AEC=\frac{\text{ Minor arc+ Major arc}}{2}\\\\m\angle AEC=(94+166)/(2)\\\\m\angle AEC=(260)/(2)\\\\m\angle AEC=130^\circ

Since ∠ AEC and ∠BEC are supplementary angles.

So, it becomes,


\angle AEC+\angle BEC=1806\circ\\\\ 130^\circ+\angle BEC=180\circ\\\\\angle BEC=180^\circ-130^\circ=50^\circ

Hence, the measure of ∠BEC = 50°.

∠BEC is formed inside a circle by two intersecting chords. If minor arc BD = 94 and-example-1
answered
User Yogeesh
by
8.6k points
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