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Calculate the pH for an aqueous solution that contains 2.15 x 10^-4 M hydroxide ion OH

Calculate the pH for an aqueous solution that contains 2.15 x 10^-4 M hydroxide ion OH
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Calculate the pH for an aqueous solution that contains 2.15 x 10^-4 M hydroxide ion OH

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User Ramayac
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pOH = -log(5.15 x 10-4) = 3.29

pH = 14 - pOH = 14 - 3.29 = 10.71

(if theres any mistake with my answer please do correct :D)
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User Jose Raul Perera
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