Question

Multiply the following polynomial and write the resulting polynomial in descending order. (3x-8)(2x^2+4x-9)

Value of the coefficient of the x^3 term is

Value of the coefficient of the x^2 term is

Value of the coefficient of the x term is

The value of the constant is

Answer 1

`(3x-8)(2x^2+4x-9)=6x^3+12x^2-27x-16x^2-32x+72=6x^3-4x^2-59x+72`

Value of the coefficient of the
`x^3` term is
`\boxed{6}`

Value of the coefficient of the
`x^2` term is
`\boxed{-4}`

Value of the coefficient of the x term is
`\boxed{-59}`

The value of the constant is
`\boxed{72}`

:)