Question

Find the value of the lesser root of x2 - 7x + 12 = 0.

A) -3
B) -1
C) 1
D) 3

Answer 1

the answer to your question is D) 3

Answer 2

`x_1 = (-(-7) - √((-7)^2 -4(1)(12)))/(2(1))= (7-1)/(2)= 3`

`x_2 = (-(-7) + √((-7)^2 -4(1)(12)))/(2(1))= (7+1)/(2)= 4`

So then since we want the lesser root the correct answer on this case is:

D) 3

Explanation:

For this case we have the followin expression:

`x^2 -7x +12=0`

For this case we can use the quadratic formula in order to solve it, given by:

`x = (-b \pm √(b^2 -4ac))/(2a)`

And on this case a = 1, b = -7, c = 12. And if we replace we got:

`x_1 = (-(-7) - √((-7)^2 -4(1)(12)))/(2(1))= (7-1)/(2)= 3`

`x_2 = (-(-7) + √((-7)^2 -4(1)(12)))/(2(1))= (7+1)/(2)= 4`

So then since we want the lesser root the correct answer on this case is:

D) 3