Question

PLEASE HELP ME!!!!!!!!!!!!!
Let f(x)=x^2+7 and g(x)=x-3/x find (f o g) (-8)

Answer 1

x=-56 that is the answer

Answer 2

`f{\circ }g(-8)=(781)/(8)`

Explanation:

We have been given two function
`f(x)=x^2+7` and
`g(x)=(x-3)/(x)`. We are asked to find
`f{\circ }g(-8)`.

By the definition of composite functions
`f{\circ}g(x)=f(x)\cdot g(x)`.

`f{\circ }g(-8)=f(-8)\cdot g(-8)`

`f(-8)=(-8)^2+7`

`f(-8)=64+7`

`f(-8)=71`

`g(-8)=(-8-3)/(-8)`

`g(-8)=(-11)/(-8)`

`g(-8)=(11)/(8)`

`f{\circ }g(-8)=71\cdot (11)/(8)`

`f{\circ }g(-8)=(781)/(8)`

Therefore,
`f{\circ}g(x)=(781)/(8)`.