Question

This is confusing. help plz

Answer 1

`a=-1`, because the parabola has the maximum, not the minimum, (∩)

The Vertex form of a parabola equation:
V(-3;4), so:

`f(x)=a(x-p)^2+q`

`f(x)=-1(x+3)^2+4`

*
`f(x)=-(x+3)^2+4`

The zeros and the conix form of a parabola equation:

`x_1=-5`

`x_2=-1`

`f(x)=a(x-x_1)(x-x_2)`, so:

*
`f(x)=-(x+5)(x+1)`

We can also use the general form of a parabola:

`f(x)=ax^2+bx+c`


`f(x)=-(x+5)(x+1)=-(x^2+x+5x+5)=-x^2-x-5x-5=-x^2-6x-5`

*
`f(x)=-x^2-6x-5`

The answers: A, C, E

:)