Find the lateral area of the square pyramid shown, to the nearest whole number. A. 7294 yd2 B. 3192 yd2 C. 4758 yd2 D. 3647 yd2

Question

asked Oct 3, 2018 85.5k views

2 Answers

Dfinn · Answer 1 · 2018-10-08T20:28:36+0000

Answer:

The correct answer is option D

Explanation:

The lateral area of pyramid is

$l * √((w/2)^2 + h^2)  + w * √((l/2)^2 + h^2) \\$

Where

$l = 42 yd\\w = 42 yd\\h = 38 yd\\$

Substituting all these values in above equation, we get -

$42 * \sqrt{((42)/(2))^2 + 38^2 } \\ + 42 * \sqrt{((42)/(2))^2 + 38^2 } \\\\= 2 * 42 * 43.41\\= 3647 yd^2\\$