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How do you completely factor 2x^3-8x^2-10x?

How do you completely factor 2x^3-8x^2-10x?
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How do you completely factor 2x^3-8x^2-10x?

asked
User KindaTechy
by
7.8k points

1 Answer

4 votes

1) First divide by 2


x^(3) -4 x^(2) -5x

2) And then factor

x(x-5)(x+1)

answered
User Phillipwei
by
8.2k points
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