Question

Which of the following identifies the maximum number of moles of products formed when 0.90 moles of ScCl3 is mixed with 0.90 moles KOH in water solution?

ScCl3 +3KOH --> Sc(OH)3 +3KCl

Sc(OH)3. KCl
0.30 0.30
0.30 1.00
0.30 0.90
0.90 0.30
0.90 0.90

Answer 1

0.30 0.90

Hope that helps!

Answer 2

ScCl3 +3KOH so KOH with the "3" is the limiting factor here

so 0.9 moles of KOH will create 0.9 moles of KCl

as KCl is also 3x of Sc(OH)3, there sho6uld be 0.9/3 = 0.3 moles of Sc(OH)3

ans is C