Question

What is the vertex of the point x^2-32x+156

Answer 1

the x value of the vertex in form
ax²+bx+c=y
is =-b/2a

so
given
1x²-32x+156
vertex is -(-32)/(2*1)=32/2=16
to find y value, input 16 for x

16²-32(16)+156
265-512+156
-256+156
-100


vertex is (16,-100)