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(0,-4),(1,0),(2,2) find a quadratic function in standard form for each set of points.

asked
User DTown
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8.4k points

1 Answer

2 votes
We are given the points
(0,-4),(1,0),(2,2)
The standard form a quadratic function (in terms of x) is
y = Ax2 + Bx + C
Subsitute the points
-4 = 0 + 0 + C
C = -4

0 = A + B - 4

2 = 4A + 2B - 4

Solve for A and B
A = -1
B = 5

The function is
y = -x2 + 5x - 4
answered
User Acvcu
by
8.7k points

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