Question

If the horizontal component of a net force is 68 newtons and the angle made by the net force with the horizontal is 19.2°, what is the value of the net force?

Answer 1

72.0 N

Step-by-step explanation:

The horizontal component of the net force is given by:

`F_x = F cos \theta`

where

F is the magnitude of the net force

`\theta` is the angle between the net force and the horizontal.

In this problem, we know:

- the horizontal component,
`F_x = 68 N`

- the angle,
`\theta=19.2^(\circ)`

Therefore, we can re-arrange the equation to find the magnitude of the net force:

`F=(F_x)/(cos \theta)=(68 N)/(cos 19.2^(\circ))=72.0 N`