Question

Using the following thermochemical data, what is the change in enthalpy for the following reaction?

Ca(OH)2(aq) + 2HCl(aq) → CaCl2(aq) + 2H2O(l)
CaO(s)+2HCl(aq)→CaCl2(aq)+H2O(l), ΔH= –186kJ
CaO(s)+H2O(l)→Ca(OH)2(aq), ΔH= –65.1 kJ

Answer 1

In calculating the change in enthalpy in a certain reaction, it is important to remember that it is the sum of the enthapy of formation for the substances involved in the reaction.

CaO(s)+2HCl(aq)→CaCl2(aq)+H2O(l) ΔH= –186kJ
Ca(OH)2(aq) → CaO(s)+H2O(l) ΔH= 65.1 kJ
Ca(OH)2(aq) + 2HCl(aq) → CaCl2(aq) + 2H2O(l) ΔH= -120.9 kJ