Question

What else would need to be congruent to show that ABC = XYZ by AAS ? ( see picture)

Answer 1

The answer is C because it's Makes the triangles congruent by AAS

Answer 2

Answer: C.
`\angle{B}\cong\angle{Y}`

Explanation:

• AAS theorem says that if two angles and a non-included side of a triangle are congruent to two angles and a non-included side of other triangle then the triangles are congruent.

In the given picture , we have ΔABC and ΔXYZ

Given :
`\angle{A}\cong\angle{X}`

`\overline{AC}\cong\overline{XZ}`

To show both the triangles are congruent by AAS theorem , we need one more angle such that the given sides must remains non-included.

Thus,
`\angle{B}` must be congruent to
`\angle{Y}` to show ΔABC ≅ ΔXYZ by AAS.

[If we take
`\angle{C}\cong\angle{Z}`, then the triangles are congruent by ASA]