Find all complex solutions of 2x^2+3x+5=0 using the quadratic equation.

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asked Jun 15, 2018 61.1k views

1 Answer

Raaghav · Answer 1 · 2018-06-19T11:06:57+0000

2x^2 + 3x + 5 = 0
a = 2 b = 3 and c = 5
x = [-b +-sq root(b^2 -4ac)] / 2a
x = [-3 +-sq root(9 -4*2*5)] / 4
x = [-3 +-sq root(9 - 40)] / 4
x = -(3 / 4) + sq root (-36) / 4
x = -(3 / 4) - sq root (-36) / 4

Find all complex solutions of 2x^2+3x+5=0 using the quadratic equation.

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