Question

What are the two solutions of x^2 – 2x – 4 = –3x + 9?

the y-coordinates of the y-intercepts of the graphs of y = x^2 – 2x – 4 and y = –3x + 9
the x-coordinates of the x-intercepts of the graphs of y = x^2 – 2x – 4 and y = –3x + 9
the y-coordinates of the intersection points of the graphs of y = x^2 – 2x – 4 and y = –3x + 9
the x-coordinates of the intersection points of the graphs of y = x^2 – 2x – 4 and y = –3x + 9

Answer 1

y = x^2 – 2x – 4 and y = –3x + 9 are two separate graphs

when they intersect (NOT intercept), x^2 – 2x – 4 = –3x + 9

so the intersection point's x-coordinate is a solution

ans is D