Question

What is the equation of the line that passes through (4,0) and (6,-8)?

Answer 1

Hello : let A(4,0) B(6,-8)
the slope is : (YB - YA)/(XB -XA)
(-8-0)/(6-4) = -4
an equation is : y=ax+b a is a slope

y = -4x +b

the line through point (4,0) : 0 = -4(4)+b
b = 16
the equation is : y =-4x+16