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How many real number solutions does the equation have ? 0=-4x^2+7x-8

How many real number solutions does the equation have ? 0=-4x^2+7x-8
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4 votes
How many real number solutions does the equation have ?
0=-4x^2+7x-8

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User Simon Elliston Ball
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8.2k points

1 Answer

4 votes
hello :
-4x² +7x-8 = 0
delta = b²-4ac a=-4 b=7 c=-8
delta = (7)²-4(-4)(-8) =-79
(delta) < 0... no solution in : R
answered
User Nemanja Todorovic
by
7.7k points
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