Question

How many moles of nitrogen, N, are in 82.0 g of nitrous oxide, N2O?

Answer 1

moles of N20 is: 82/(14*2+16)= 1.86 (moles)
In N2O there are 2 nitrogen so moles of nitrogen will be: 1.86 * 2 = 3.72 (moles)

Answer 2

Answer : The number of moles of nitrogen present in nitrous oxide are 3.72 moles.

Explanation : Given,

Mass of = 82.0 g

Molar mass of
`N_2O` = 44 g/mole

First we have to calculate the moles of
`N_2O`.

`\text{ Moles of }N_2O=\frac{\text{ Mass of }N_2O}{\text{ Molar mass of }N_2O}=(82.0g)/(44g/mole)=1.86moles`

Now we have to calculate the moles of nitrogen in nitrous oxide.

In nitrous oxide
`N_2O`, there are 2 moles of nitrogen and 1 mole of oxygen.

As, 1 moles of
`N_2O` contains 2 moles of nitrogen

So, 1.86 moles of
`N_2O` contains
`1.86* 2=3.72moles` of nitrogen

Therefore, the number of moles of nitrogen present in nitrous oxide are 3.72 moles.