How many grams of solid baso4 will form when ba2so4 react with 25mL of .50 M Ba(NO3)2

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asked Jul 12, 2018 88.9k views

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Bernardo Duarte · Answer 1 · 2018-07-16T13:45:15+0000

Na2SO4+ Ba(NO3)2 --> 2NaNO3 + BaSO4
0.0125 0.0125
mole of Ba(NO3)2 = 0.025 * 0.5 = 0.0125 (mole)
The grams of BaSO4 = 0.0125 * ( 137+32+16*4) = 2.9125(g)

How many grams of solid baso4 will form when ba2so4 react with 25mL of .50 M Ba(NO3)2

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