How many moles of sulfur dioxide are held inside a 37.4L canister at a pressure of 0.55 atm and a temperature of 45.0 C ?

Question

asked Mar 21, 2018 38.0k views

1 Answer

Mdpoleto · Answer 1 · 2018-03-27T22:32:30+0000

PV=nRT n=PV/RT
R=.0821 atm x L
Mol x K
T=318K
P=.55atm
V=37.4L

n= (.55atm) (37.4L) /
.0821atm x L (318k)
mol x K
n= .79 mol of sulfur dioxide