H=-16t^2+v0t+h0 feet

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asked Feb 27, 2018 126k views

1 Answer

Martin Ring · Answer 1 · 2018-03-05T19:56:23+0000

THe function h(t)=-16t^2+v0t+h0 describes the height in feet above the ground h(t) of an object thrown vertically from a height of h0 feet, with an initial velocity of v0 feet

H=-16t^2+v0t+h0 feet

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