asked 65.6k views
4 votes
Can somebody help me find the 11th term of the geometric sequence 6,30,150,750?

asked
User Vickey
by
8.3k points

1 Answer

7 votes
geometrice
an=a1(r)^(n-1)
a1=first term
r=common ratio
n=which term

we see first term is 6
common ratio is a term divided by the previous term
30/6=5
r=5

an=6(5)^(n-1)
11th term
a11=6(5)^(11-1)
a11=6(5)^10
a11=6(9765625)
a11=58593750
the 11th term is 58593750

answered
User Joseph Wood
by
8.7k points

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