Question

If 12^x2+^5x-4=12^2x+6, what could be the value of x?

Answer 1

Since the both have the same base 12 you can write like thus
X^2+5x-4=2x+6
X^2+5x-4-2x-6=0
X^2+3x-10=0
(X-2)(X+5)
X-2=0. X+5=0
X=2. And X=-5

Answer 2

`x=-5, x=2`

Explanation:

we have

`12^{(x^(2)+5x-4)}=12^((2x+6))`

Since the both have the same base
`12`

`{(x^(2)+5x-4)}={(2x+6)}`

`x^(2)+5x-4-2x-6=0`

`x^(2)+3x-10=0`

Using a graphing tool ------> resolve the quadratic equation

see the attached figure

The solutions are

`x=-5, x=2`