Question

Calculate the number of grams of oxygen required to convert 23.0 g of glucose to CO2 and H2O.

Answer 1

i think that it equal to co=3 h=2 o=1

Answer 2

Mr of C6H12O6= (12*6)+(12*1)+(16*6)=180
Mr of O2=(16*2)=32

If 180 g of glucose requires 6*32 g of oxygen
38 g of glucose would need 6*32/180 * 38=40.53 g of oxygen
ans=40.53

mr of CO2=44
If 180 g of glucose gives 44*6 g of CO2
therefore 38 g of it gives 44*6/180 * 38 = 55.73 g of CO2