Question

I THINK ITS A OR B. Write the ratios for sin A and cos A. The triangle is not drawn to scale. Please help!!!

Answer 1

Answer: The answer is
`(B)~\sin A=(48)/(50),~~\cos A=(14)/(50).`

Step-by-step explanation: We are given a right-angled triangle ABC, where ∠C = 90°, AC = 14 units, BC = 48 units and AB = 50 units.

For angle A,

hypotenuse, h = the longest side = AB,

base, b = adjacent side = AC

and

Perpendicular, p = side perpendicular to the base 'b' = BC.

Therefore, from ΔABC, we have

`\sin A=(p)/(h)=(BC)/(AB)=(48)/(50),\\\\\cos A=(b)/(h)=(AC)/(AB)=(14)/(50).`

Thus, (B) is the correct option that gives the ratio for sin A and cos A.